貝拉盧娜

★ 6.4 播放：67萬 更新：2026-05-13

When Luna, a battered wife, and Bela, an empowered artist, meet for the first time, their hearts will be freed by the people and society that chain them.

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劇情簡介

When Luna, a battered wife, and Bela, an empowered artist, meet for the first time, their hearts will be freed by the people and society that chain them.

導演精選

巴里·林登

 愛爾蘭，Redmond Barry(瑞安·奧尼爾 Ryan O'Neal 飾）從小和母親寄居在舅舅家，后來愛上了他的表姐Nora。Nora的父親卻想把她許配給一個英格蘭將軍John Quin。于是Barry向Quin提出決斗，決斗中Barry射中了Quin，誤以為將他殺 死了，匆忙逃離家鄉(xiāng)。路上他遭遇搶劫，走投無路只能加入英國軍隊。在軍隊中他才得知，其實Quin并沒有死。Barry從英軍中出逃，卻加入了普魯士軍。戰(zhàn)爭結(jié)束后他成了普魯士軍官Potzdorf的心腹，更讓他去監(jiān)視一個在普魯士的愛爾蘭間諜。Barry卻和這個愛爾蘭騎士惺惺相惜，愛爾蘭騎士帶他出入賭場，收獲頗豐。Barry覺得自己應該找個有錢的女人，于是盯上了Lyndon爵士的夫人Lady Lyndon。Lyndon爵士病重身亡，一年后，Barry和Lady Lyndon結(jié)婚，也成了一名貴族，改名為Barry Lyndon。但Lyndon爵士和Lady Lyndon的兒子Bullingdon卻十分不喜歡Barry，Barry也預感到自己的未來將會毀于Bullingdon手中.....

曼谷保鏢2

　　⊙《曼谷保鏢2》的故事：　　影片故事講述拔泰王錦魯飾演的東南亞某小國特工翁坤，為了調(diào)查一伙恐怖份子，秘密潛入泰國曼谷執(zhí)行任務(wù)，并化裝成為流行歌星，混入唱片公司追查。他老婆并不知道他的真實身份，因為翁坤是個十足的“妻管嚴”，但要命的是，他在泰國無可救藥愛上了一個漂亮美眉……與此同時，恐怖份子也要發(fā)動大規(guī)模襲擊了，翁坤如何能制止這場破壞？　　⊙《曼谷保鏢2》的看點：　　繼2005年大賣座的第一集之后，《曼谷保鏢》于今年拍出了續(xù)集，有“泰國周星馳”之稱泰國喜劇明星拔泰王錦魯繼續(xù)自編自導自演，繼續(xù)請來《拳霸》東尼·嘉參與演出。影片向周星馳、成龍電影偷了師，并且自己惡搞了《拳霸》《冬蔭功》等片，拔泰王錦魯（《拳霸》另一主演）演出非常出彩過癮。Tony Jaa則之是客串身份，在片中有一場打斗，另外自己還拿《冬蔭功》開涮，十分的“搞”。

摩斯拉

　　Shipwreck survivors are found on Beiru Island (Infanto t?), which was previously used for atomic tests. The interior is amazingly free of radiation effects, and they believe that they were protected by a special juice that was given to them by the island's residents. A joint expedition of Rolisican and Japanese scientists explores Beiru and discovers many curious things, including two women only one foot (30 centimeters) high. Unscrupulous expedition leader Clark Nelson abducts the women and puts them in a vaudeville show. But their sweet singing contains a telepathic cry for help to Mothra, a gigantic moth that is worshiped as a deity by the island people. The giant monster heeds the call of the women and heads to Tokyo, wreaking destruction in its path.